Can't concatenate other strings to BinaryToString

[Relive]

msgbox(0, '', BinaryToString(0x41) & chr(117)) ; Spells "Au"
msgbox(0, '', Chr(116) & Chr(111) & BinaryToString(0x49) & chr(116)) ; Spells "toIt"
msgbox(0, '', 'Auto' & BinaryToString(0x49) & chr(116)) ; Spells "AutoIt"

Any kind of string concatenation after BinaryToString() is "cut off".

[jchd18]

You are misusing the parameter to BinaryToString.

msgbox(0, '', BinaryToString("0x41") & chr(117)) ; Spells "Au"
msgbox(0, '', Chr(116) & Chr(111) & BinaryToString("0x49") & chr(116)) ; Spells "toIt"
msgbox(0, '', 'Auto' & BinaryToString("0x49") & chr(116)) ; Spells "AutoIt"

Please, next time, post in the Help forum before creating a ticket.

[Relive]

This ticket may need to be reopened as I may have found a bug in BinaryToString(). Inserting 0x41 and 0x49 to BinaryMid() to extract 1 byte each, which is seemingly redundant, but actually fixed the problem.

msgbox(0, '', BinaryToString(BinaryMid(0x41, 1, 1)) & chr(117)) ; Spells "Au"
msgbox(0, '', Chr(116) & Chr(111) & BinaryToString(BinaryMid(0x49, 1, 1)) & chr(116)) ; Spells "toIt"
msgbox(0, '', 'Auto' & BinaryToString(BinaryMid(0x49, 1, 1)) & chr(116)) ; Spells "AutoIt"

The binary values written this way have hidden padded zeros and BinaryToString() has some parsing bug. In another view, when doing Binary(73), it returns 0x49000000. But I specifically wrote "0x49" in my argument, and thus this ticket was submitted.

[jchd18]

No, you submitted BinaryToString(0x49) and not BinaryToString("0x49") as explained in my previous answer.
Please post in the help forum (not here) which "parsing bug" you found in BinaryToString().