therks Posted September 21, 2007 Posted September 21, 2007 $aFixed = DriveGetDrive('fixed') $aRemovable = DriveGetDrive('removable') ? My AutoIt Stuff | My Github
James Posted September 21, 2007 Posted September 21, 2007 (edited) As far as I know you can only get one. At a time. Although thinking about it you could go through a loop to retrieve them and then show the variables in a MsgBox() Edited September 21, 2007 by JamesB Blog - Seriously epic web hosting - Twitter - GitHub - Cachet HQ
SleepyXtreme Posted September 21, 2007 Posted September 21, 2007 #include <Array.au3> dim $Var[1] $aFixed = DriveGetDrive('fixed') $aRemovable = DriveGetDrive('removable') For $x = 1 to $aFixed[0] $Var[0] +=1 _ArrayAdd( $Var,$x) Next For $i = 1 to $aRemovable[0] $Var[0] +=1 _ArrayAdd( $Var,$i) Next This is just a rough idea, but basically it gets all the info from both and combines it into 1 array, $Var. $Var[0] is the total number of items it catches. let me know if this helps:)
Gif Posted September 21, 2007 Posted September 21, 2007 (edited) more like this:#include <Array.au3> dim $Var[1] $aFixed = DriveGetDrive('fixed') $aRemovable = DriveGetDrive('removable') For $x = 1 to $aFixed[0] $Var[0] +=1 _ArrayAdd($Var, $aFixed[$x]) Next For $i = 1 to $aRemovable[0] $Var[0] +=1 _ArrayAdd($Var, $aRemovable[$i]) Next _ArrayDisplay($Var) Edited September 21, 2007 by Gif
therks Posted September 22, 2007 Posted September 22, 2007 Quite easily actually. My AutoIt Stuff | My Github
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