Ilounah Posted March 14 Posted March 14 Hi ๐ย Hello, when I incorporate this code as an add-in within Excel, the data doesn't transfer to cells B12, B14, and B16 as expected. However, when I place the code in a module within the workbook itself, it works correctly. 1. Prompt the user to select an Excel file using the file dialog box. 2. Open the selected Excel file. 3. Retrieve the file location, file name, and the name of the first sheet in the Excel file. 4. Place this information in specific cells of a worksheet (Sheet3 using codename). 5. Close the selected workbook and quit Excel. 6. Display a message box informing the user that the process is complete. Thank youย ๐ expandcollapse popupSub SelectExcelFile_() Dim selectedFile As Variant Dim fileLocation As String Dim excelApp As Object Dim Workbook As Object ' Open the file dialog box With Application.FileDialog(msoFileDialogFilePicker) .AllowMultiSelect = False .Title = "Select an Excel File" ' Show only Excel files in the dialog box .Filters.Clear .Filters.Add "Excel Files", "*.xls; *.xlsx; *.xlsm" If .Show = -1 Then ' User clicked OK ' Get the selected file path selectedFile = .SelectedItems(1) ' Create an instance of Excel and open the selected file Set excelApp = CreateObject("Excel.Application") Set Workbook = excelApp.Workbooks.Open(selectedFile) ' Get the file location fileLocation = Left(selectedFile, InStrRev(selectedFile, "\") - 1) ' Place the file location, file name, and sheet name in cells B12, B14, and B16 respectively Sheet3.Range("B12").Value = fileLocation Sheet3.Range("B14").Value = Workbook.Name Sheet3.Range("B16").Value = Workbook.Sheets(1).Name ' Close the selected workbook and quit Excel Workbook.Close excelApp.Quit ' Clean up the objects Set Workbook = Nothing Set excelApp = Nothing MsgBox "Done, Updating File Location.." & vbCrLf & vbCrLf & "Please Open the file:" & vbCrLf & Sheet3.Range("B14").Value, vbInformation, "Successful _path Folder Location." End If End With End Sub ย
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