StringRegEx not working when inserting a variable in the pattern

[TheOne23]

Hi Guys,

Can you help  me figure out why my test script is not working? it is showing "0" which is not match where I tried to put same value of string already.

It worked when it is not in a variable format.

Example:

This works - StringRegExp($short_description_text_1,'(po)(?!.*\1\b)',$STR_REGEXPMATCH)

This does not work - StringRegExp($short_description_text_1,$string,$STR_REGEXPMATCH)

 

#include <MsgBoxConstants.au3>
#include <StringConstants.au3>

local $short_description_text_1 = "po"
local $keywords_split_2 = "po"
local $string = "'("& $keywords_split_2 &")(?!.*\1\b)'"
;~ MsgBox(0,"",$string)
;~ MsgBox(0,"result: ",StringRegExp($short_description_text_1, "'(" & $keywords_split_2 & ")(?!.*\1\b)'" ,$STR_REGEXPMATCH))
MsgBox(0,"result: ",StringRegExp($short_description_text_1,$string,$STR_REGEXPMATCH))

 

[Andreik]

Your string it's stored in $short_description_text_1 and your pattern in $string. Of course it cannot find '(po)(?!.*\1\b)' in po. I suppose you want to swap these two.

MsgBox(0,"result: ",StringRegExp($string, $short_description_text_1, $STR_REGEXPMATCH))

 

Edited July 17, 2023 by Andreik

[pixelsearch]

@TheOne23 the superfluous single quote delimiter seems to create the issue :

; Local $string = "'(" & $keywords_split_2 & ")(?!.*\1\b)'"
Local $string = "(" & $keywords_split_2 & ")(?!.*\1\b)"

Does it solve your problem ?
Edited July 17, 2023 by pixelsearch

[mikell]

18 minutes ago, pixelsearch said:

Does it solve your problem ?

If used in the code in post #1, with the OP's requirements for sure it will. In this case the assertion returns true

[TheOne23]

Hi pixelsearch and Mikell,

Thank you very much on your inputs. It is now solved. 👍