Remove string until character

[dersiniar]

I have looked different help files but havent find what i need. 

I have word  "  this is LOL word "  How to remove all string untill LOL included. I cant use StringRight($result2, 11) because text  " This is "  and  " word " can change to different words, only word " LOL is fixed

Edited March 10, 2022 by dersiniar

[Jos]

Use StringInstr() to find the start of the word and then use StringMid() with the found start position.  

Give it a try and post the code you tried that isn't working.

[dersiniar]

11 minutes ago, Jos said:

Use StringInstr() to find the start of the word and then use StringMid() with the found start position.  

Give it a try and post the code you tried that isn't working.

Hmm think that wont work cos i need to get that last word what comes after LOL. Since last word is changeable variable, cant use StringRight or anyother that depends on character count. 

[Jos]

Yes it does because you know the length of the word you are searching!   So simply add that.

Edited March 10, 2022 by Jos

[dersiniar]

10 minutes ago, Jos said:

Yes it does because you know the length of the word you are searching!   So simply add that.

 

16 minutes ago, dersiniar said:

Since last word is changeable variable,

No i do not know length, only thing is know is word LOL that's always there, And i need to get string that comes after it and that string is always different word and length. So is first string always different word and length

[Jos]

Post your example code showing the issue with the different input strings and the expected output, after  which we can discuss this further, because I totally do not understand your point here as the StringInStr() will handle that variable prefix string length issue as far as I can see.

Edited March 10, 2022 by Jos

[jchd]

Or use a regex!

Local $sWord = "LoL"
Local $aIn = ["  this is LOL word ", "philology is LOL word ", " LOL this is Lol word "]
For $s In $aIn
    ConsoleWrite("'" & $s & "'  ->  '" & StringRegExpReplace($s, "(?i).*\b" & $sWord & "\b", "") & "'" & @LF)
Next

The trigger word can be any case but must be a separate word: "lol" in "philology" doesn't match. Only the last occurence of the trigger word counts. You may want to remove spaces from the output, or have other requirement. Just tell.

[dersiniar]

19 hours ago, jchd said:

Or use a regex!

Local $sWord = "LoL"
Local $aIn = ["  this is LOL word ", "philology is LOL word ", " LOL this is Lol word "]
For $s In $aIn
    ConsoleWrite("'" & $s & "'  ->  '" & StringRegExpReplace($s, "(?i).*\b" & $sWord & "\b", "") & "'" & @LF)
Next

The trigger word can be any case but must be a separate word: "lol" in "philology" doesn't match. Only the last occurence of the trigger word counts. You may want to remove spaces from the output, or have other requirement. Just tell.

I get error  

 ==> Variable must be of type "Object".:
For $s In $aIn
For $s In $aIn^ ERROR

[jchd]

Works for me, clearly.

Copy/paste the exact content I posted in a new .au3 and run it verbatim.

[mikell]

Local $sWord = "LoL"
Local $aIn = ["  this is LOL word1 ", "philology is LOL word2 ", " LOL this is Lol word3 "]
For $s In $aIn
   ; ConsoleWrite("'" & $s & "'  ->  '" & StringRegExpReplace($s, "(?i).*\b" & $sWord & "\b", "") & "'" & @LF)
    $w = StringStripWS(StringTrimLeft($s, StringInStr($s, $sWord, 0, -1) + StringLen($sWord) -1), 3)
    ConsoleWrite("'" & $s & "'  ->  '" & $w & "'" & @LF)
Next