Find a number in an array

[Felicitas]

Hello again,

i have an array like this 

aArray = -7, -4, 0, 1, 6, 8

I want to find the lowest number except the negative ones an zero (should be 1)

Any good idea?

Thank you so much

[TheDcoder]

Just loop through it and keep track of the lower number you have encountered till now. I don't think there is a more efficient way to do it without the array being sorted.

[Zedna]

Look at _ArrayMin()

EDIT: Sorry I overlooked needed condition for zero/negative numbers, so as TheDCoder said ...

 

here example from helpfile:

#include <Array.au3>

Local $avArray = StringSplit("4,2,06,8,12,5", ",")

MsgBox(0,'Min String value', _ArrayMin($avArray, 0, 1))
MsgBox(0,'Min Numeric value', _ArrayMin($avArray, 1, 0))

 

Edited October 19, 2021 by Zedna

[mikell]

?

#include <Array.au3>

Local $avArray = StringSplit("-7,-4,0,1,6,8", ",", 2)

For $i = UBound($avArray) -1 to 0 step -1
    If $avArray[$i] = 0 Then _ArrayDelete($avArray, $i)
    $avArray[$i] = Abs($avArray[$i])
Next
;_ArrayDisplay($avArray)
MsgBox(0,'Min Numeric value', _ArrayMin($avArray, 1, 0))

 

[Felicitas]

Thank you so much! It works for me with this code:

local $FindGreaterO =_ArrayExtract($new,-1,-1,4,4)
For $i = 0 To UBound($FindGreaterO)-1 Step 1
    $FindGreaterO[$i] = StringReplace($FindGreaterO[$i],",",".")
    $FindGreaterO[$i] = Number($FindGreaterO[$i])
Next

For $i = UBound($FindGreaterO) -1 to 0 step -1
    If $FindGreaterO[$i] <= 0.01 Then _ArrayDelete($FindGreaterO, $i)
Next
$FindNull=StringReplace(_ArrayMin($FindGreaterO),".",",")
ConsoleWrite($FindGreaterO)