Help to assign variável with numbers

[RafaelGioffi]

Hey guys, help me with a question... I have a script with 36 variables ($n0, $n1, $n2 ...) and I would like to read the 36 variables automatically.

I used some example tests ...

<code>

For $i = 0 to 36 step 1

Assign("n" & $i, $i)

Next

</code>

[Melba23]

RafaelGioffi,

I suggest using an array to store those variables - reading the Arrays tutorial in the Wiki will give you the idea.

M23

[jugador]

for $i = 0 to 36
   assign("n" & $i , $i)
Next

for $i = 0 to 36
   ConsoleWrite(eval("n" & $i ) & @CRLF)
Next

 

[RafaelGioffi]

Thanks a lot guys.. I will test these solutions.. 

[RafaelGioffi]

Hey guys! I made the mentioned solutions and it was like that...

Func ZeraArray()
For $i = 0 To 36 - 1 Step 1
   $sorteados[$i] = $i
   Assign("lbl" & $i, $sorteados[$i], 4)
   ConsoleWrite(Eval("lbl" & $i))
   GUICtrlSetData(Eval("lbl" & $i), Eval("lbl" & $i))
Next

EndFunc

It turns out that when executing, this happens... The labels are $lbl0, $lbl1, $lbl2 and etc. However, they are changing the values of other variables such as $Label1, $txtVezes and other variables, except those defined in the function.

I think I'll have to do a manual...

GuiCtrlSetData($lbl0, $sorteados[0])
GuiCtrlSetData($lbl1, $sorteados[1])
...

Sad, but true...

Edited August 1, 2021 by RafaelGioffi

[JockoDundee]

1 hour ago, RafaelGioffi said:

Sad, but true...

Neither sad or true.

Your approach is muddled.  You were given two suggestions, the first, by @Melba23was designed to show you the best way to rewrite your code, I.e., using an array.  The second suggestion, by @jugadorwas designed to help make work the code you had so far.

But the solution was not to combine the two.

All you need to do is declare an array of 36 control IDs, $lbl[36], assign them when you create the controls, and then you can access them thru via $lbl[$i] in a for loop.

 

 

Edited August 1, 2021 by JockoDundee

[jugador]

Use Array as advise by @Melba23 & @JockoDundee for better control over your code.
but if you still insist then use Execute

GUICtrlSetData(Execute("lbl" & $i), Eval("lbl" & $i))

 

[jchd]

Eval() and friends is the worst idea in this case, like in almost all use cases.

Use an array!

[RafaelGioffi]

12 hours ago, JockoDundee said:

Neither sad or true.

Your approach is muddled.  You were given two suggestions, the first, by @Melba23was designed to show you the best way to rewrite your code, I.e., using an array.  The second suggestion, by @jugadorwas designed to help make work the code you had so far.

But the solution was not to combine the two.

All you need to do is declare an array of 36 control IDs, $lbl[36], assign them when you create the controls, and then you can access them thru via $lbl[$i] in a for loop.

 

 

I didn't know I could use array to define elements like label and text... Very good! Problem solved!
Thank you very much for your help!

[JockoDundee]

11 hours ago, jugador said:

but if you still insist then use Execute

GUICtrlSetData(Execute("lbl" & $i), Eval("lbl" & $i))

I don’t think this actually works as intended.  Execute(), unlike Eval(), require variable names to have a preceding $.

In any event, I think you could use either:

GUICtrlSetData(Execute("$lbl" & $i), $i)

or 

GUICtrlSetData(Eval("lbl" & $i), $i)

 

[jugador]

yes $ sign is needed, bit careless while editing @RafaelGioffi  posted code.
Thanks @JockoDundee for correcting my mistake.