Passing parameter as variable in Run function

[max23ed]

Hi, as the title says, here is my code but its not working 

; Get the parameter from open file dialog
GUICtrlSetData($locationtxt, FileOpenDialog("Select the program", '', "Supported files (*.exe;*.msi;*.reg;*.inf)|Executable Files (*.exe)|Microsoft Installer files (*.msi)|Registry files (*.reg)|Inf files (*.inf)", 3))

; store the value in a variable 
 $abc = GUICtrlRead($locationtxt)
 ; Run the program and pass the parameter value
            Run("ussf.exe "  & $abc  )
            
  ; If i do it this way, its working but i want the parameter value from the open dialog not fixed
  Run("ussf.exe C:\Users\project\ccsetup563.exe")

Please show me how i can do it and i'm sorry if someone asked about this topic before.

[david1337]

Hi max23ed,

Try with Shellexecute.

ShellExecute("ussf.exe", $abc)

 

[max23ed]

Hey David, Thank you for the reply, its working now perfectly. Thank you. 

[david1337]

You're welcome

[Zedna]

In Run() try to specify working directory and also put parameter into quotes:

Run('ussf.exe "'  & $abc & '"', @ScriptDir)

Also try absolute path to EXE file.

Edited October 22, 2019 by Zedna