Regex help

[lee321987]

Hello, I'm trying to match the second to last line of this:

foo
C:\
foobar
foobar x
C:\temp\dir
Last line with chars

Here's my code:

$test = 'foo' & @CRLF
$test &= 'C:\' & @CRLF
$test &= 'foobar' & @CRLF
$test &= 'hello' & @CRLF
$test &= 'C:\temp\dir' & @CRLF
$test &= 'Last line with chars' & @CRLF
$test &= @CRLF
$test &= @CRLF
$result = StringRegExp($test, '(?m)^C:\\.*$Last.*')
MsgBox(0, '', $result)

I'm trying to match line "C:\temp\dir".  Anyone have any ideas?

Edited May 5, 2019 by lee321987

[iamtheky]

In addition to modifying the expression, if you want the return you need to use the correct flag on stringregexp.  These efforts are only better in that they return the desired result, they are not optimal. 

one regex, one not:

$test = 'foo' & @CRLF
$test &= 'C:\' & @CRLF
$test &= 'foobar' & @CRLF
$test &= 'hello' & @CRLF
$test &= 'C:\temp\dir' & @CRLF
$test &= 'Last line with chars' & @CRLF
$test &= @CRLF
$test &= @CRLF


msgbox(0, '' , stringregexp(StringStripWS($test , 2) ,  @CRLF & "(.*?)" & @CRLF & ".*?\z" , 3)[0])

;~ msgbox(0,'' , stringmid(stringstripws($test , 2) , stringinstr(stringstripws($test , 2) , @LF , 0 , -2) , stringinstr(stringstripws($test , 2) , @LF , 0 , -1) - stringinstr(stringstripws($test , 2) , @LF , 0 , -2) ))

 

[lee321987]

Thanks for the help, but (I'm sorry) I should have said that "C:\temp\dir" won't always be the second-to-last line.

I need to match the string - not just "the second to last line".

[iamtheky]

so you just need to know if that string is present or not?

$test = 'foo' & @CRLF
$test &= 'C:\' & @CRLF
$test &= 'foobar' & @CRLF
$test &= 'hello' & @CRLF
$test &= 'C:\temp\dir' & @CRLF
$test &= 'Last line with chars' & @CRLF
$test &= @CRLF
$test &= @CRLF



msgbox(0, '' , StringInStr($test , 'C:\temp\dir') > 1 ? "Match" : "No Match")

 

[lee321987]

Oops.  I meant -- yes, but I want to know how to do it with regex.

(edit:  accidentally replied before finishing text)

Edited May 5, 2019 by lee321987

[mikell]

This one returns the n'th non-empty last line  

$test = 'foo' & @CRLF
$test &= 'C:\' & @CRLF
$test &= 'foobar' & @CRLF
$test &= 'hello' & @CRLF
$test &= 'C:\temp\dir' & @CRLF
$test &= 'Last line with chars' & @CRLF
$test &= @CRLF
$test &= @CRLF

$n = -2  ; number of the line to get
Msgbox(0,"", StringRegExpReplace($test, '(?ms).*?(^\N*\S\N*$)\s*(?:(?1)\s*){0,' & -$n-1 & '}\z', "$1") )

 

[lee321987]

Ok I'm REALLY sorry, I need to clarify:

I won't always know what line "C:\temp\dir" is on.

I just need to make sure there is a line that starts with "C:\" and it has some text after "C:\" before the next newline (because the line "C:\" will always be present).

[mikell]

Ah OK 

Try this one

StringRegExp($test, '(?im)^C:\\\N*\S\N*$')

It only checks "if there is a line that starts with "C:\" and it has some text after "C:\" "

Edited May 5, 2019 by mikell

[lee321987]

24 minutes ago, mikell said:

StringRegExp($test, '(?im)^C:\\\N*\S\N*$')

That did it!!  Thanks to both of you for helping!