Can you pass an array as a literal in the function call?

[Mbee]

I couldn't find anything on point, which leads me to suspect it's not possible.  What I'd like to do is call a function like this:
 

$iStat = MyFunc( [[4], [7]] )

Func MyFunc( $argInputAra )
EndFunc

Of course I can almost as easily declare and initialize an array and then pass that to the function, but since the values are always literals, it would be a bit easier.  By the way, I might pass an array with more elements, but I'd deal with that using UBound().

Edited March 18, 2019 by Mbee

[Mbee]

OK, I just found a few developer requests about that feature, and it was declined, for reasons I think I understand. Never mind... 😶

[Nine]

You could pass it as a string like :

$iStat = MyFunc("4|7")

Func MyFunc ($strInputArray)
Local $aStr = StringSplit ($strInputArray, "|", $STR_NOCOUNT)

EndFunc

See how I use Local here  - - Never mind him.

[Bilgus]

I don't know if this is faster or even cleaner than doing the stringsplit thing but here is another way

Test()
Test1(Call(MyArr))

Func Test($aArray = Call(MyArr))
    ConsoleWrite(IsArray($aArray) & "!")
    _ArrayDisplay($aArray)
Endfunc

Func Test1($aArray)
    ConsoleWrite(IsArray($aArray) & "!")
    _ArrayDisplay($aArray)
Endfunc

Func MyArr()
    Local Const $a[5] = [1, 2, 3, 4, 5]
    Return $a
EndFunc

 

Edited March 18, 2019 by Bilgus

[jchd]

You can even streamline things:

$iStat = MyFunc(StringSplit("4|7", "|", $STR_NOCOUNT))

Func MyFunc ($aInputArray)
    ...
EndFunc

Bonus: this still allows you to pass an existing array in other invokations.
Drawback: all array entries are string type.

[Mbee]

Thanks, all!  The people on these AutoIt fora are so very kind and generous! Take a bow, folks! 

 

[Mbee]

On 3/17/2019 at 9:06 PM, Nine said:

You could pass it as a string like :

See how I use Local here  - - Never mind him.

[Nine]

25 minutes ago, Mbee said: