Problems looping over leading zeroes

[billbobaggins]

I have a script that I've made that I want to loop 999999 times, and input a number into a text file, but I want all of the leading zeroes to remain so each loop always has six digits. For instance on each loop you may get the following:

Loop 1: 000001

Loop 2: 000002

Loop3: 000003

Loop 4: 000004

All the way up to 999999, so you may eventually have 102056 etc once it gets to that part in the loop.

 

My script so far looks like this:

Global $Start = "000000"

for $i=0 to 999999
   Send($Start)
   Send("{ENTER}")
   Sleep(50)
   $Start = $Start + 1
   next

However it's removing the leading zeros. Is there a proper way to do this? I've tried the string formatting part of autoit but I can't seem to get it to work with my use case.

Any help would be greatly appreciated! 

[careca]

had similar issue.

Edited January 2, 2018 by careca

[billbobaggins]

I'm still a little bit confused as to how to solve this in my case. Tried following the examples in the provided thread but I end up incriminating how many zeros I have instead of incriminating the number by 1 while making sure it's always six digits.  

[water]

Example:

$iCount = 1
ConsoleWrite(StringFormat('%06s', $iCount) & @CRLF)
$iCount = 999
ConsoleWrite(StringFormat('%06s', $iCount) & @CRLF)

 

[careca]

25 minutes ago, billbobaggins said:

incriminating the number

Well, what did the number do?

[Earthshine]

incriminating numbers always get you.... lol. increment is the word. in C/C++/C# i just use sprintf() but water answered you direct.

Edited January 2, 2018 by Earthshine

[billbobaggins]

1 hour ago, water said:

Example:

$iCount = 1
ConsoleWrite(StringFormat('%06s', $iCount) & @CRLF)
$iCount = 999
ConsoleWrite(StringFormat('%06s', $iCount) & @CRLF)

Excellent, this works! thank you.