Help for StringRegExpReplace

[tempman]

Hello forums,

How do I replace this

$sInput = "10.0.0.12>>>local\User1;IIS2\user2"

to this

$sOutput = "10.0.0.12>>>User1;user2;"

I manage to do it with functions StringInStr and StringMid, but not with StringRegExpReplace.

Thank you!

Edited November 13, 2017 by tempman
Have additional question

[jchd]

This?

Local $sInput = "10.0.0.12>>>local\User1;IIS2\user2"
Local $sOutput = StringRegExpReplace($sInput, "(?<=>|;)[^>]*?\\", "")
ConsoleWrite($sOutput & @LF)

 

[tempman]

Once again, everything look easy when it's done by the pros!

[tempman]

I do not want to spam the forum, but I have an additional question

How do I replace this 

$sInput = "10.0.0.12>>>Jordan;Jason Smith;Ron;"

to this 

$sOutput = "10.0.0.12>>>Jordan;Ron;"

So, any string with space (Jason Smith;) is no need

Thank you!

[SlackerAl]

\w+\s\w+;

word space word ;

have a play here: regex test

[tempman]

Nice one SlackerAl!

I just add '.', if there is someone with middle name

$sInput = "10.0.0.12>>>Jordan;Jason Smith;Ron;William Henry Gates III;Mike"
Local $sOutput = StringRegExpReplace($sInput, ".\w+\s+\w+", "")
MsgBox(64, "", $sOutput)

 

[mikell]

StringRegExpReplace($sInput, "\w+\s+[^;]+;", "")

[jguinch]

Another one :

StringRegExpReplace($sInput, "\w+(\s+\w+)+(?:;|$)", "")

[mikell]

1 hour ago, jguinch said:

The non-capturing group is useless