StringInStr Not Working :(

[luger]

Hello, My English is not good. 

example(100-100)

Func example($add)
    Local $a
    ConsoleWrite(VarGetType($add) & @CRLF)
    $a = String($add)
    ConsoleWrite(VarGetType($a) & @CRLF)
    ConsoleWrite(StringInStr($a, "-"))
EndFunc

Int32
String
0>Exit code: 0    Time: 0.09297

Why does not work? 
The result should be 4.. :(

Note: @AutoItVersion ;-->v3.3.14.2

Edited January 11, 2017 by luger

[jchd]

In my book, 100 - 100 = 0

You probably mean "100-100"

[Subz]

Why would it be 4? 100-100 = 0, so your parameter is 0.  You would need to use example("100-100") to return a string.

[luger]

17 minutes ago, jchd said:

In my book, 100 - 100 = 0

You probably mean "100-100"

I forgot to calculate, variable.. You are right. I understand. Thanks for the answer.

Right: "100-100"

Edited January 11, 2017 by luger

[luger]

16 minutes ago, Subz said:

Why would it be 4? 100-100 = 0, so your parameter is 0.  You would need to use example("100-100") to return a string.

I noticed the calculation later.

example("100-100")

Func example($add)
    ConsoleWrite(VarGetType($add) & @CRLF)
    ConsoleWrite(StringInStr($add, "-"))
EndFunc

Return: 4

Thanks for the answer :) My problem is resolved. I understand.

Edited January 11, 2017 by luger