Include function with If statement

[Miliardsto]

Is there possibility to do it like this?

Cause as I see compiler doesn't see If statement in case of #include functions.

It includes these two files all time.

If $var == True Then 
    #include 'func/funcsByTabs/main_Moda.au3'
Else
    #include 'func/funcsByTabs/main_Others.au3'
EndIf

 

[BrewManNH]

No there isn't a way to do this, as all directives (preceeded by #) are processed before compile. There's no way for the compiler to read your code and execute it prior to compiling. Make 2 different scripts or deal with it inside the code and just include both files, I'm sure the size difference won't be all that much.

[careca]

What about

If $var == True Then 
    $Var1 = 'func/funcsByTabs/main_Moda.au3'
Else
    $Var1 = 'func/funcsByTabs/main_Others.au3'
EndIf

#include $Var1

But im not sure it works.

[BrewManNH]

Won't work, the includes have to be literal strings, they can't be variables because you'd have to run the script to get the value it's supposed to contain, and the compiler doesn't run the script.