Openfiledialog getting file name

[Agentwho]

Hello, I added openfiledialog function into my script. I would like to get opened file name without direction. 

Example : Selected files in openfiledialog "C:\Users\Terron\Desktop\newfile.txt"  =>   "newfile.txt"  <<= I would like to get this name

Which function should I add in the script?     

Thanks...

[Jos]

Perhaps: _PathSplit() ?

Jos

[AutoBert]

also possible :

$sRet="C:\Program Files\AutoIt3\Examples\GUI\merlin.gif"    ;this simulate the returnstring of fileopendialog without  $FD_MULTISELECT
$sWanted=StringMid($sRet,StringInStr($sRet,'\',0,-1)+1)     ;this is the combination of funcs you can use
MsgBox(0,'filename only',$sWanted)

if $FD_MULTISELECT is used you have to use StringSplit:

#include <Array.au3>
$sRet=  "C:\Program Files\AutoIt3\Examples\GUI|logo4.gif|merlin.gif"    ;this simulate the returnstring of fileopendialog with $FD_MULTISELECT
$aWanted=StringSplit($sRet,'|',2)
_arraydisplay($aWanted) ;this is the array of returnstring REMEMBER $aWandted[0]=Path, all others filenames without path

 

Edited July 12, 2016 by AutoBert

[Agentwho]

Just now, AutoBert said:

also possible :

$sRet="C:\Program Files\AutoIt3\Examples\GUI\merlin.gif"    ;this simulate the returnstring of fileopendialog without  $FD_MULTISELECT
$sWanted=StringMid($sRet,StringInStr($sRet,'\',0,-1)+1)     ;this is the combination of funcs you can use
MsgBox(0,'filename only',$sWanted)

if $FD_MULTISELECT is used you have to use StringSplit:

#include <Array.au3>
$sRet=  "C:\Program Files\AutoIt3\Examples\GUI|logo4.gif|merlin.gif"    ;this simulate the returnstring of fileopendialog with $FD_MULTISELECT
$aWanted=StringSplit($sRet,'|',2)
_arraydisplay($aWanted) ;this is the array of returnstring REMEMBER $aWandted[0]=Path, all others filenames without path

 

It is working. Thanks a lot.