FileChangeDir Question

[232showtime]

Hi just want to ask why am I getting the return success value of destination path "C:\yahoo\1" ?

#include <MsgBoxConstants.au3>
#include <WinAPIFiles.au3>
#include <WindowsConstants.au3>
#include <WinAPI.au3>

Example()

Func Example()

    Local $sFileSaveDialog = FileSaveDialog("Choose a filename.", "", "All Files(*.*)", $FD_PATHMUSTEXIST + $FD_MULTISELECT)
    $SaveDir = FileCopy($sFileSaveDialog, "", $FC_OVERWRITE)
    $GetPath = _WinAPI_GetFullPathName($sFileSaveDialog)
    ; Display the current working directory.
    MsgBox($MB_SYSTEMMODAL, "", "The current working directory: " & @CRLF & $GetPath)

    $sChangeDir = FileChangeDir("C:\yahoo") ;--> Path I want to get "C:\yahoo"
    $GetPath1 = _WinAPI_GetFullPathName($sChangeDir)
    If $sChangeDir = 0 Then
        MsgBox($MB_SYSTEMMODAL, "", "Error")
        Exit
    Else
        MsgBox($MB_SYSTEMMODAL, "", "Succes" & @CRLF & $GetPath1) ;--> Path I got "C:\yahoo\1"
    EndIf


EndFunc   ;==>Example

I ran the example in helpfile and its working fine, is this a bug???

[mikell]

Please try

$GetPath1 = _WinAPI_GetFullPathName(@WorkingDir)

Edit
In this case though, the winapi thing is redundant. Why not directly check @workingdir ?

Edited July 9, 2016 by mikell

[232showtime]

OMG, Im a total noob... never thought of that... thank you...

Edited July 9, 2016 by 232showtime

[mikell]

The help file is your best friend - you shouldn't lose touch with it  

[232showtime]

@mikell

sorry bout this but sometimes I get confused with so many codes , I always check help file, google, and auto it wiki...

 

Quote

Edit
In this case though, the winapi thing is redundant. Why not directly check @workingdir ?

 

I tried like this and I got Value of 1, instead of string path...

#include <MsgBoxConstants.au3>
#include <WinAPIFiles.au3>
#include <WindowsConstants.au3>
#include <WinAPI.au3>

Example()

Func Example()

    Local $sFileSaveDialog = FileSaveDialog("Choose a filename.", "", "All Files(*.*)", $FD_PATHMUSTEXIST + $FD_MULTISELECT)
    $SaveDir = FileCopy($sFileSaveDialog, "C:\yahoo", $FC_OVERWRITE)
    $GetPath = _WinAPI_GetFullPathName($sFileSaveDialog)
    ; Display the current working directory.
    MsgBox($MB_SYSTEMMODAL, "", "The current working directory: " & @CRLF & $GetPath)

    $sChangeDir = FileChangeDir(@WorkingDir) ;--> Path I want to get "C:\yahoo"
;~     $GetPath1 = _WinAPI_GetFullPathName(@WorkingDir)
;~     If $sChangeDir = 0 Then
;~         MsgBox($MB_SYSTEMMODAL, "", "Error")
;~         Exit
;~     Else
        MsgBox($MB_SYSTEMMODAL, "", "Succes" & @CRLF & $sChangeDir) ;--> Path I got "1"
;~     EndIf


EndFunc   ;==>Example

 

[Melba23]

232showtime,

Does this make it clearer?

#include <MsgBoxConstants.au3>
#include <FileConstants.au3>

Example()

Func Example()

    Local $sFileSaveDialog = FileSaveDialog("Choose a filename.", "", "All Files(*.*)", $FD_PATHMUSTEXIST + $FD_MULTISELECT)

    ;$GetPath = _WinAPI_GetFullPathName($sFileSaveDialog) ; Why do you do this, you already get the full path returned from the function call

    ; Display the current working directory.
    MsgBox($MB_SYSTEMMODAL, "", "The current working directory: " & @CRLF & $sFileSaveDialog)

    ; Now change the working folder
    $iRet = FileChangeDir("M:\Program")
    If $iRet = 0 Then
        MsgBox($MB_SYSTEMMODAL, "", "Error")
        Exit
    Else
        MsgBox($MB_SYSTEMMODAL, "", "Succes" & @CRLF & @WorkingDir)
    EndIf


EndFunc   ;==>Example

M23

[232showtime]

@Melba23

first time user of $sFileSaveDialog, no idea that it will return the full path returned from function call

basicallyI wanted to get the filepath of the files that I copied using FileCopy. I did so many workaround and I landed on my 1st post of script. its clear now . by the way is there any other way to get the file path of the file that I copied using filecopy???

Local $sFileSaveDialog = FileSaveDialog("Choose a filename.", "", "All Files(*.*)", $FD_PATHMUSTEXIST + $FD_MULTISELECT)
    
    $SaveDir = FileCopy($sFileSaveDialog, "C:\yahoo", $FC_OVERWRITE); ---------------------in this line I Want to Get "C:\yahoo" instead of the current working dir... in my case Save Dialog box working dir is C:\Users\user\Pictures.. so im getting the path of C:\Users\user\Pictures instead of "C:\yahoo"
    
    
    $GetPath = _WinAPI_GetFullPathName($SaveDir) ;--> I want t see what will happen here
    ; Display the current working directory.
    MsgBox($MB_SYSTEMMODAL, "", "The current working directory: " & @CRLF & $GetPath)

many thanks @Melba23 & @mikell

[mikell]

Hmm it seems that you are confusing several things. Please try this :

#include <FileConstants.au3>
#Include <Array.au3>
#include <StringConstants.au3>

Local $sFileOpenDialog = FileOpenDialog("Choose a filename.", "", "All Files(*.*)", $FD_PATHMUSTEXIST + $FD_MULTISELECT)

If not @error Then
   MsgBox(0,"FileOpenDialog return", $sFileOpenDialog)
   $aSave = StringSplit($sFileOpenDialog, "|")
  _ArrayDisplay($aSave, "FileOpenDialog array")
  $destDir = "C:\yahoo\"    ;<<< don't forget the backslash !
  For $i = 2 to $aSave[0]
     FileCopy($aSave[1] & "\" & $aSave[$i], $destDir, $FC_CREATEPATH + $FC_OVERWRITE)
  Next
EndIf
ShellExecute($destDir )