topten Posted March 27, 2016 Share Posted March 27, 2016 I need to replace all spaces with symbol "+". I tried to use stringregexpreplace $string = "string string" $test = StringRegExpReplace($string,"(\s)","+") When I have "string string" it is replaced by "string+string", but when I have "string string" (double space in between) I also have "string+string", instead of "string++string" How can I match single space? note that I've already used (\s) (\s+) (\s?) (\s{1}) - none of them worked Link to comment Share on other sites More sharing options...
jchd Posted March 27, 2016 Share Posted March 27, 2016 59 minutes ago, topten said: when I have "string string" (double space in between) I also have "string+string", instead of "string++string" No. $string = "string string string or else" $test = StringRegExpReplace($string, "(\s)", "+") ConsoleWrite($test & @LF) $test = StringReplace($string, " ", "+") ConsoleWrite($test & @LF) Skysnake 1 This wonderful site allows debugging and testing regular expressions (many flavors available). An absolute must have in your bookmarks.Another excellent RegExp tutorial. Don't forget downloading your copy of up-to-date pcretest.exe and pcregrep.exe hereRegExp tutorial: enough to get startedPCRE v8.33 regexp documentation latest available release and currently implemented in AutoIt beta. SQLitespeed is another feature-rich premier SQLite manager (includes import/export). Well worth a try.SQLite Expert (freeware Personal Edition or payware Pro version) is a very useful SQLite database manager.An excellent eBook covering almost every aspect of SQLite3: a must-read for anyone doing serious work.SQL tutorial (covers "generic" SQL, but most of it applies to SQLite as well)A work-in-progress SQLite3 tutorial. Don't miss other LxyzTHW pages!SQLite official website with full documentation (may be newer than the SQLite library that comes standard with AutoIt) Link to comment Share on other sites More sharing options...
topten Posted March 27, 2016 Author Share Posted March 27, 2016 Right! my mistake I was using $test = StringRegExpReplace($string,"(\s+)","+") Thanx a lot! Link to comment Share on other sites More sharing options...
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