rodiney Posted February 18, 2016 Posted February 18, 2016 I want to do an if in the array. in my array the value can be 0. $ Array [0] = 0 as I do to check if array is empty? if $ array [0] = "" the endif It works well?
InunoTaishou Posted February 18, 2016 Posted February 18, 2016 Are you checking if the whole array is empty? #include <Array.au3> Global const $SORT_DESCENDING = 1 Global $array[] = [3, 2, 1, 5, 1, "Test", "String", 99, 3, 0] Global $array2[] = [0, 0, 0, 0, "", "", 0, 0] _ArraySort($array, $SORT_DESCENDING) _ArraySort($array2, $SORT_DESCENDING) If ($array[0] or StringLen($array)) Then MsgBox("", "", "The first array is not empty") Else MsgBox("", "", "The first array is empty") EndIf If ($array2[0] or StringLen($array2)) Then MsgBox("", "", "The second array is not empty") Else MsgBox("", "", "The second array is empty") EndIf rodiney 1
czardas Posted February 18, 2016 Posted February 18, 2016 (edited) 3 hours ago, rodiney said: It works well? No it does not work well. To test the first element, you could use: If $aArray[0] == "" Then MsgBox(0, "Contents", "nothing") To test if the array actually contains elements, you should use: If UBound($aArray) = 0 Then MsgBox(0, "Contents", "zero elements") These examples will only work with 1D arrays. Edited February 18, 2016 by czardas SkysLastChance and toto22 2 operator64 ArrayWorkshop
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