LovelyJane Posted December 10, 2014 Posted December 10, 2014 Hello, sorry if this has been asked before but I was wondering how do you create a new line or line break in MsgBox "message", example: Func ShowMessage() MsgBox(64, "title", "line 1 line 2 line 3") EndFunc Call ("ShowMessage") So it appears as, Title of message box Message first line "line 1" Message second line "line 2" Message third line "line 3" and not appears as, Title of message box Message first line "line 1 line 2 line 3" Message second line blank Message third line blank
Solution gottygolly Posted December 10, 2014 Solution Posted December 10, 2014 (edited) Example() Func Example() MsgBox(64,"Title","Line 1"&@crlf&"Line 2"&@crlf&"Line 3") EndFunc That? Edited December 10, 2014 by gottygolly
water Posted December 10, 2014 Posted December 10, 2014 "line 1" & @CRLF & "line 2" & @CRLF & "line 3" My UDFs and Tutorials: Spoiler UDFs: Active Directory (NEW 2024-07-28 - Version 1.6.3.0) - Download - General Help & Support - Example Scripts - Wiki ExcelChart (2017-07-21 - Version 0.4.0.1) - Download - General Help & Support - Example Scripts OutlookEX (2021-11-16 - Version 1.7.0.0) - Download - General Help & Support - Example Scripts - Wiki OutlookEX_GUI (2021-04-13 - Version 1.4.0.0) - Download Outlook Tools (2019-07-22 - Version 0.6.0.0) - Download - General Help & Support - Wiki PowerPoint (2021-08-31 - Version 1.5.0.0) - Download - General Help & Support - Example Scripts - Wiki Task Scheduler (2022-07-28 - Version 1.6.0.1) - Download - General Help & Support - Wiki Standard UDFs: Excel - Example Scripts - Wiki Word - Wiki Tutorials: ADO - Wiki WebDriver - Wiki
LovelyJane Posted December 10, 2014 Author Posted December 10, 2014 (edited) Thank you! I did not know &@CRLF& represents line break or new line. Edited December 10, 2014 by LovelyJane
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