How to replace parts of the same part of the keyword in the text?

i2i8 · August 24, 2014

Full

<plugin
         id="com.adobe.flexbuilder.codemodel"
         download-size="0"
         install-size="0"
         version="4.5.1.313231"/>

   <plugin
         id="com.adobe.flexbuilder.crimson"
         download-size="0"
         install-size="0"
         version="4.5.1.313231"/>

   <plugin
         id="com.adobe.flexbuilder.editors.derived"
         download-size="0"
         install-size="0"
         version="4.5.1.313231"/>

   <plugin
         id="com.adobe.flexbuilder.flex"
         download-size="0"
         install-size="0"
         version="4.5.1.313231"/>

   <plugin
         id="com.adobe.flexbuilder.multisdk"
         download-size="0"
         install-size="0"
         version="4.5.1.313231"/>

   <plugin
         id="com.adobe.flexbuilder.mxmlmodel"
         download-size="0"
         install-size="0"
         version="4.5.1.313231"/>

   <plugin
         id="com.adobe.flexbuilder.project"
         download-size="0"
         install-size="0"
         version="4.5.1.313231"/>

Replacing

<plugin
         id="com.adobe.flexbuilder.project"
         download-size="0"
         install-size="0"
         version="4.5.1.313231"/>

to

<plugin
         id="com.adobe.flexbuilder.project"
         download-size="0"
         install-size="0"
         version="0.0.0"/>

mikell · August 24, 2014

?

$txt = FileRead("1.txt")
$txt = StringRegExpReplace($txt, '(?<=version=")([^"]+)', "0.0.0")
FileWrite("2.txt", $txt)

sahsanu · August 24, 2014

For me it isn't clear if you wants to replace all version fields or just project part so if you want to replace all version fields go ahead with mikell regexp (mikell is really good with regular expressions ). if you just want to replace field version for project part you could use something like this:

$txt = FileRead("1.txt")
$txt = StringRegExpReplace($txt, '(?s)(.*project.*?version=")(.*?)(".*)', "${1}0.0.0${3}")
FileWrite("2.txt", $txt)

Cheers,

sahsanu

guinness · August 24, 2014

Maybe a StringReplace() would be suffice for what they want.

i2i8 · August 24, 2014

For me it isn't clear if you wants to replace all version fields or just project part so if you want to replace all version fields go ahead with mikell regexp (mikell is really good with regular expressions ). if you just want to replace field version for project part you could use something like this:
$txt = FileRead("1.txt")
$txt = StringRegExpReplace($txt, '(?s)(.*project.*?version=")(.*?)(".*)', "${1}0.0.0${3}")
FileWrite("2.txt", $txt)
Cheers,

sahsanu

Very nice, you solved my problem! thank you!

i2i8 · August 24, 2014

But I don't understand what this means?

$txt = StringRegExpReplace($txt, '(?s)(.*project.*?version=")(.*?)(".*)', "${1}0.0.0${3}")

Jos · August 24, 2014

But I don't understand what this means?

$txt = StringRegExpReplace($txt, '(?s)(.*project.*?version=")(.*?)(".*)', "${1}0.0.0${3}")

Helpfile is your friend.

Jos

sahsanu · August 24, 2014

But I don't understand what this means?

$txt = StringRegExpReplace($txt, '(?s)(.*project.*?version=")(.*?)(".*)', "${1}0.0.0${3}")

As Jos said, you could take a look to help file, in StringRegExp you have a good refrence for regular expressions.

And this is what the regular expression does:

(?s)(.*project.*?version=")(.*?)(".*)

Options: Case sensitive; Exact spacing; Dot doesn't match line breaks; ^$ match at line breaks; Greedy quantifiers; Regex syntax only

Use these options for the whole regular expression «(?s)»

&Dot matches line breaks «s»

Match the regex below and capture its match into backreference number 1 «(.*project.*?version=")»

Match any single character «.*»

Between zero and unlimited times, as many times as possible, giving back as needed (greedy) «*»

Match the character string “project” literally (case sensitive) «project»

Match any single character «.*?»

Between zero and unlimited times, as few times as possible, expanding as needed (lazy) «*?»

Match the character string “version="” literally (case sensitive) «version="»

Match the regex below and capture its match into backreference number 2 «(.*?)»

Match any single character «.*?»

Between zero and unlimited times, as few times as possible, expanding as needed (lazy) «*?»

Match the regex below and capture its match into backreference number 3 «(".*)»

Match the character “"” literally «"»

Match any single character «.*»

Between zero and unlimited times, as many times as possible, giving back as needed (greedy) «*»

${1}0.0.0${3}

Insert the text that was last matched by capturing group number 1 «${1}»

Insert the character string “0.0.0” literally «0.0.0»

Insert the text that was last matched by capturing group number 3 «${3}»

Cheers,

sahsanu

i2i8 · August 24, 2014

As Jos said, you could take a look to help file, in StringRegExp you have a good refrence for regular expressions.

And this is what the regular expression does:
(?s)(.*project.*?version=")(.*?)(".*)
Options: Case sensitive; Exact spacing; Dot doesn't match line breaks; ^$ match at line breaks; Greedy quantifiers; Regex syntax only
Use these options for the whole regular expression «(?s)»
   &Dot matches line breaks «s»
Match the regex below and capture its match into backreference number 1 «(.*project.*?version=")»
   Match any single character «.*»
      Between zero and unlimited times, as many times as possible, giving back as needed (greedy) «*»
   Match the character string “project” literally (case sensitive) «project»
   Match any single character «.*?»
      Between zero and unlimited times, as few times as possible, expanding as needed (lazy) «*?»
   Match the character string “version="” literally (case sensitive) «version="»
Match the regex below and capture its match into backreference number 2 «(.*?)»
   Match any single character «.*?»
      Between zero and unlimited times, as few times as possible, expanding as needed (lazy) «*?»
Match the regex below and capture its match into backreference number 3 «(".*)»
   Match the character “"” literally «"»
   Match any single character «.*»
      Between zero and unlimited times, as many times as possible, giving back as needed (greedy) «*»
${1}0.0.0${3}
Insert the text that was last matched by capturing group number 1 «${1}»
Insert the character string “0.0.0” literally «0.0.0»
Insert the text that was last matched by capturing group number 3 «${3}»

Cheers,

sahsanu

Thank you, thank you very much.

mikell · August 24, 2014

sahsanu

Thanks

BTW this one can be done without using backreference(s)

K can be nicely used as a kind of "lookbehind including undefinite quantifiers"

$txt = StringRegExpReplace($txt, '(?s).*project.*?version="\K([^"]+)', "0.0.0")

sahsanu · August 24, 2014

BTW this one can be done without using backreference(s)
K can be nicely used as a kind of "lookbehind including undefinite quantifiers"
$txt = StringRegExpReplace($txt, '(?s).*project.*?version="\K([^"]+)', "0.0.0")

That is a nice use of K. I've never used it, indeed I didn't know that it exists, so thank you, every day we learn something new

Cheers,

sahsanu

i2i8 · August 25, 2014

error

Local $feature = FileRead("C:\featured.xml")
ConsoleWrite('All content:' & $feature & @CR)
Local $feature = StringRegExpReplace($feature, '(?s).*com.adobe.flexbuilder.project*?version="\K([^"]+)', "0.0.0")
ConsoleWrite('After replace:' & $feature & @CR)

The first ConsoleWrite can be output all strings, but the next step there is this kind of error:

Local $feature = StringRegExpReplace($feature, '(?s).*com.adobe.flexbuilder.project*?version="\K([^"]+)', "0.0.0")
Local $feature = StringRegExpReplace(^ ERROR

Why?

Edited August 25, 2014 by i2i8

t1ck3ts · August 25, 2014

Another great site to help you with RegEx is http://www.regexr.com/
Its the only site thats worked my head around RegEx xD

guinness · August 25, 2014

Another great site to help you with RegEx is http://www.regexr.com/
Its the only site thats worked my head around RegEx xD

It's a good site, though have found it to be a little buggy as of late.

mikell · August 25, 2014

i2i8,

- When you update $feature you must not redeclare it, else you get a "Variable used without being declared" error

- When copying the expression you forgot a dot after 'project'

Local $feature = FileRead("featured.xml")
;ConsoleWrite('All content:' & $feature & @CR)
$feature = StringRegExpReplace($feature, '(?s).*com.adobe.flexbuilder.project.*?version="\K([^"]+)', "0.0.0")
ConsoleWrite('After replace:' & $feature & @CR)

i2i8 · August 25, 2014

i2i8,

- When you update $feature you must not redeclare it, else you get a "Variable used without being declared" error

- When copying the expression you forgot a dot after 'project'
Local $feature = FileRead("featured.xml")
;ConsoleWrite('All content:' & $feature & @CR)
$feature = StringRegExpReplace($feature, '(?s).*com.adobe.flexbuilder.project.*?version="\K([^"]+)', "0.0.0")
ConsoleWrite('After replace:' & $feature & @CR)

AHA, I understand.Thank you very much!

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How to replace parts of the same part of the keyword in the text?

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