Convert Scientific number in array

[dar100111]

Hey All!

Anyone know how to convert one of my columns to date from scientific value by chance in my RDL column?

Thanks!

[0]|DEST|HOUSEBILL|WGT|STATUS|CONSOL|RDL
[1]|ABE |H230145016  |414|Ready|TRUCK       |1.14041730900001e+017
[2]|ATL |H230145006  |511|Ready|TRUCK       |1.14041730900001e+017
 

[jguinch]

what kind of time would you have from 1.14041730900001e+017 ?

[dar100111]

To be more specific.  I want to grab the value in my array that's coming from my sql query and convert, and replace with "mm-dd-yy hh:mm" format so I can put into a listview on my gui.

For some reason I had some logic to do this in my sqlquery it is usually a decimal and the function I have is convering into scientific.

Thanks!

This function below is bringing query results into my array.  It's taking a decimal from my query and converting in my RDL column.

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Func QueryToArray($p_connection, $p_query)
 Local $i, $j, $l_objQuery, $l_result
 $l_objQuery = ObjCreate("ADODB.Recordset")
 if @error = 1 then return ''
 $l_objQuery.Open($p_query, $p_connection)
 if $l_objQuery.State = 0 then return ''
 Dim $l_result[1][$l_objQuery.Fields.Count]
 For $j = 0 to $l_objQuery.Fields.Count - 1
  $l_result[0][$j] = $l_objQuery.Fields($j).Name
 Next
 $i = 1
 if $l_objQuery.EOF then return $l_result
    Do
        For $j = 0 To $l_objQuery.Fields.Count - 1
   if $i < UBound($l_result) Then
    $l_result[$i][$j] = $l_objQuery.Fields.Item($j).value
   Else
    ReDim $l_result[Ubound($l_result, 1) + 1][$l_objQuery.Fields.Count]
    $l_result[$i][$j] = $l_objQuery.Fields.Item($j).value
   EndIf
        Next
        $l_objQuery.MoveNext
        $i = $i + 1
    Until $l_objQuery.EOF
 return $l_result
EndFunc


$l_objConn = ObjCreate("ADODB.Connection")
$l_objConn.Open("DRIVER={IBM DB2 ODBC DRIVER};HOSTNAME=" & $p_branch & "." & $p_branch & ".ei;PORT=50000;DATABASE=" & $p_branch & ";PROTOCOL=TCPIP;UID=" & $p_user & ";PWD=" & $p_password)
if @error Then
    MsgBox(0, "ERROR", "Failed to connect to the database")
    Exit
Else
    MsgBox(0, "Success!", "Connection TCS.gtwy")
EndIf

;$rbills_query = LoadSQLFile("ready_bills.sql")
$results = QueryToArray($l_objConn, $rbills_query)
_ArrayDisplay($results)
$l_objConn.Close ; ==> Close the database

Edited April 10, 2014 by dar100111

[jguinch]

My question was : what is the "mm-dd-yy 00:00" value for 1.14041730900001e+017 ?

[jdelaney]

If you paste the value returned here, into excel, it can convert to date time...maybe it's the same for sql?

$string = StringRegExpReplace(1.14041730900001e+017,"[^\d]","")
ConsoleWrite($string & @CRLF)
$string = StringRegExpReplace($string,"(\d{7})(.*)","$1.$2")
ConsoleWrite($string & @CRLF)

1140417.30900001017

Prior to the decimal is the count of days, from some start date...after is 24 * the remainder, to determin the hour/min/sec/etc.

Edited April 10, 2014 by jdelaney

[dar100111]

Yeah I know you can add 1900 and that would be current year I'm trying to figure out the rest still.  First parts are pretty easy but getting the hh:mm:ss trying to figure that out out still.

[jguinch]

The return value for "1140417.30900001017" is 09/05/5022  07:24:58 for me (French Excel) ...

[dar100111]

same jguinch  if you add 19000000 that would bring you current day 20140417 and the timestamp on it should be 17:00:00.  Still trying to figure out how to convert that part.

Edited April 10, 2014 by dar100111

[jdelaney]

Whatever the decimal turns out to be, this can do it:

$Total = 24 * .30900001017
$aTotal = StringSplit($Total, ".")
$iHour = $aTotal[1]
$iTotal2 = 60 * ("." & $aTotal[2])
$aTotal2 = StringSplit($iTotal2, ".")
$iMinute = $aTotal2[1]
$iTotal3 = 60 * ("." & $aTotal2[2])
$aTotal3 = StringSplit($iTotal3, ".")
$iSecond = $aTotal3[1]

ConsoleWrite($iHour & ":" & $iMinute & ":" & $iSecond & "." & $aTotal3[2] & @CRLF  )

Edited April 10, 2014 by jdelaney

[dar100111]

Thanks Jdelaney.  I'll play around with this.  Still trying to figure out how to get 17:00:00 out of that initial string.  Thanks!

[jchd]

2014/04/17 not the current day.

[jdelaney]

How about:

$string = StringRegExpReplace(1.14041730900001e+017,"[^\d]","")
$string = StringRegExpReplace($string,"(\d{7})(.*)","$1.$2")
$aDays = StringSplit($string, ".")
$iDays = $aDays[1]+19000000

$iDays = StringRegExpReplace($iDays,"(\d{4})(\d{2})(\d{2})","$2/$3/$1")


$Total = 24 * ("." & $aDays[2])
$aTotal = StringSplit($Total, ".")
$iHour = $aTotal[1]
$iTotal2 = 60 * ("." & $aTotal[2])
$aTotal2 = StringSplit($iTotal2, ".")
$iMinute = $aTotal2[1]
$iTotal3 = 60 * ("." & $aTotal2[2])
$aTotal3 = StringSplit($iTotal3, ".")
$iSecond = $aTotal3[1]

ConsoleWrite($iDays & " " & $iHour & ":" & $iMinute & ":" & $iSecond & "." & $aTotal3[2] & @CRLF  )

output:

04/17/2014 7:24:57.600878688

Edited April 10, 2014 by jdelaney

[jchd]

Rather than gambling about how to knead this surprising large value (1.14041730900001e+017 = 114041730900001000) by removing the scientific notation exponent separator and guessing how it could be offset to magically produce a date close to current date, it would be much, really much more serious to ask ourselves where this format comes from and search which precise timestamp it represents.

The OP gave us some insight: he's grabbing his data from an IBM DB2 database. It's unlikely that this represents a julian timestamp even if we arbitrarily shift the decimal point: julianday('now') = 2456758.80446287, quite different. Then datetime(1140417.30900001) = -1590-04-03 19:24:57 and it's difficult to believe that today's applications deal with events from 1590 BC. Other standard DB2 timestamp formats use YMD human-readable strings, modulo variations in MDY, DMY, etc. Obviously offending value is not that form.

 

Notes to dar100111:

It would be enlightnening to see the query used.

Streamline your code using something like this:

Func QueryToArray($p_connection, $p_query)
    Local $l_objQuery = ObjCreate("ADODB.Recordset")
    If @error = 1 Then Return ''
    $l_objQuery.Open($p_query, $p_connection)
    If $l_objQuery.State = 0 Then Return ''

    Dim $l_result[1][$l_objQuery.Fields.Count]
    For $j = 0 To $l_objQuery.Fields.Count - 1
        $l_result[0][$j] = $l_objQuery.Fields($j).Name
    Next

    Local $l_rows = $l_objQuery.GetRows()
    _ArrayConcatenate($l_result, $l_rows)   ; requires the latest beta, else use code below
;~  ReDim $l_result[UBound($l_rows) + 1][UBound($l_result, 2)]
;~  For $i = 1 To UBound($l_result) - 1
;~      For $j = 0 To UBound($l_result, 2) - 1
;~          $l_result[$i][$j] = $l_rows[$i - 1][$j]
;~      Next
;~  Next
    Return $l_result
EndFunc   ;==>QueryToArray

It will be much faster.