Rock, Paper, Scissors in C#

[guinness]

Created in only 2 lines. The first Console.WriteLine() is not included as it's there just to report the valid values.

using System;

namespace RockPaperScissorsFinal
{
    internal class Program
    {
        private static void Main()
        {
            Console.WriteLine("(1) Rock \n(2) Paper \n(3) Scissors\nEnter your choice: ");
            do
            {
                // Nested ternary statements. What a pain to read , but hey it's only 2 lines ;) Also this uses what we've already learnt.
                string[] answers = { Console.ReadLine(), "Rock", "Paper", "Scissors", new Random().Next(1, 3).ToString() };
                Console.WriteLine(answers[0] != "1" && answers[0] != "2" && answers[0] != "3" ? "Please enter a valid value next time." : "You chose {0} and the computer chose {1} with an outcome of " + (answers[0] == answers[4] ? "the same" : (answers[0] == "1" && answers[4] == "3") || (answers[0] == "2" && answers[4] == "1") || (answers[0] == "3" && answers[4] == "2") ? "winning" : "losing") + ".", answers[int.Parse(answers[0])], answers[int.Parse(answers[4])]);
            }
            while (true);
        }
    }
}

[Mat]

How about the 1 line solution? 

[guinness]

How about the 1 line solution?

It's your work! I can't pass off your work as my own. Edited March 4, 2014 by guinness

[Mat]

When you write some code, and I fix a couple of bugs in it, that still remains your code as far as I'm concerned

Anyway, 1 line solution:

object[] answers = { Console.ReadLine(), "Rock", "Paper", "Scissors", new Random().Next(1, 3) }, write = {typeof(Console).GetMethod("WriteLine", new Type[] { typeof(string) }).Invoke(null, new object[] { (string)answers[0] != "1" && (string)answers[0] != "2" && (string)answers[0] != "3" ? "Please enter a valid value next time." : "You chose " + (string)answers[int.Parse((string)answers[0])] + " and the computer chose " + (string)answers[(int)answers[4]] + " with an outcome of " + ((string)answers[0] == answers[4].ToString() ? "the same" : ((string)answers[0] == "1" && answers[4].ToString() == "3") || ((string)answers[0] == "2" && answers[4].ToString() == "1") || ((string)answers[0] == "3" && answers[4].ToString() == "2") ? "winning" : "losing") + "." }) };

[guinness]

When you write some code, and I fix a couple of bugs in it, that still remains your code as far as I'm concerned

OK

[Richard Robertson]

Don't write code like that.

[guinness]

Don't write code like that.

Of course not.