Timer behavior and computer sleep or hibernation mode

[LazyCoder]

I made a little script to remind me, every 2 hours, to drink (yes, I'm the camel kind of programmer...) thanks to a pop-up.

But at some point, my computer went to sleep mode. OK. Nothing strange there. But when the computer woke up, I was expecting the pop-up to show. But nothing. It came later.

So I guess the timer is a local count of CPU cycles?!

But did I hit something: I happened not to have the pop-up in the defined "timer time" or at all.

I'm having trouble to reproduce this issue, so I'm looking for some more information about timer behavior.

Anyone?

[JohnOne]

You're doing it wrong.

[LazyCoder]

Very helpfull...

Someone else?

[BrewManNH]

He's sarcastically telling you that we need to see your code to make any kind of rational answer valid.

[LazyCoder]

How couldn't I get it?... Must be tired today.

Here we go:

HotKeySet("^{F9}", "Terminate")

Func Terminate()
    Exit
 EndFunc   ;==>Terminate

;;;;;;;;;;;;;;;;;;;;;;;;;
;       MAIN
;;;;;;;;;;;;;;;;;;;;;;;;;

$iDelay = 7200000 ; 2h = 7200000 ms
$tBegin = TimerInit()
$tDiff = 0
While (1)
   If $tDiff > $iDelay Then
      MsgBox(48, "REMINDER", 'Get-Water("Fontain") !!!!!')
      $tBegin = TimerInit() ; reinit timer for next pop-up
   EndIf
   Sleep(1)
   $tDiff = TimerDiff($tBegin)
WEnd

Quite simple...

Edited August 27, 2013 by LazyCoder

[JohnOne]

Perhaps you should make your function geared more toward the actual time rather than difference.

Pseudo.

When script starts, get the current time.

Calculate the time two hours from that, and test calculated time against current time every minute or whatever.

Loop

[LazyCoder]

I think I will. But I like to understand how things work. Now I know I can manage "human" elapsed time and CPU elapsed time using system date/hour and timers.

Good to know.

Thanks a lot.