Windows 2k/xp Product Key...

[bcording]

This is just an example of how to do it...You could rewrite it to return keys for office products as well. Once a RegEnum function is written you'll see an intelligent version to return office products.

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Dim $Bin
$Bin = RegRead("HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Windows NT\CurrentVersion","DigitalProductID")

InputBox("Product Key", "Your " & @OSVERSION & " product key is:", DecodeProductKey($bin), "", -1, 100, -1, -1)


Func DecodeProductKey($BinaryDPID)
    Local $bKey[15]
    Local $sKey[29]
    Local $Digits[24]
    Local $Value = 0
    Local $hi = 0
    local $n = 0
    Local $i = 0
    Local $dlen = 29
    Local $slen = 15
    Local $Result

    $Digits = StringSplit("BCDFGHJKMPQRTVWXY2346789","")

    $binaryDPID = stringmid($binaryDPID,105,30)

    For $i = 1 to 29 step 2
        $bKey[int($i / 2)] = dec(stringmid($binaryDPID,$i,2))
    next

    For $i = $dlen -1 To 0 Step -1
        If Mod(($i + 1), 6) = 0 Then
            $sKey[$i] = "-"
        Else
            $hi = 0
            For $n = $slen -1 To 0 Step -1
                $Value = Bitor(bitshift($hi ,- 8) , $bKey[$n])
                $bKey[$n] = int($Value / 24)
                $hi = mod($Value , 24)
            Next
            $sKey[$i] = $Digits[$hi +1]
        EndIf

    Next
    For $i = 0 To 28
        $Result = $Result & $sKey[$i]
    Next

    Return $Result
EndFunc

Edited March 15, 2004 by bcording

[insanepyrokid]

Wow, works great. Nice little piece of random you got going there....too bad it doesnt work on Win98, i used it at school on 98 and it just returns all B's.

[bcording]

Win9x product ID is different...or at least in a different place. BTW I have tested the DecodeProductKey function with Windows 2000, Windows XP, Office XP Pro/Std, Project 2002, Virtual PC 2004 and Visual Studio 2003 Professional. When the Registry Enumeration function is complete these will all be added...till then.

[insanepyrokid]

Is there a way to distinguish windows xp home from windows xp pro? in the pop-up box it like to see which one it is. i guess i can search registry to try to find a distinguishable string.

[bcording]

In the registry look at HKLM\SYSTEM\CurrentControlSet\Control\ProductOptions.

ProductType:

ServerNT = Server

LanmanNT = Advanced Server

WinNT = Professional or Home

ProductSuite:

Personal = Home

Terminal Server = Terminal Server

So if ProductType is WinNT and ProductSuite is Personal it is Home

Edited March 17, 2004 by bcording

[insanepyrokid]

what if product type is WinNT and product suite is left blank?

[bcording]

If it's XP then it's Professional, otherwise it's Workstation

[insanepyrokid]

Thanks. With this little code i will finally have proof that my high school uses mostly pirated software. (the computer teachers already admit to using borland compilers w/o licenses and starcraft w/o legit keys...stupid school....not that im gunna do anything about it, but ive always had a hunch that they dont have the licenses for all thier windows (they have comps ranging from win95 to nt and xp, some with the all-too-popular pirated cd key....lol

[Gene]

Thanks. With this little code i will finally have proof that my high school uses mostly pirated software. (the computer teachers already admit to using borland compilers w/o licenses and starcraft w/o legit keys...stupid school....not that im gunna do anything about it, but ive always had a hunch that they dont have the licenses for all thier windows (they have comps ranging from win95 to nt and xp, some with the all-too-popular pirated cd key....lol

There is another, less nefarious possibility...

A former employer regularly purchased (for example sake) 200 licenses and 10 CD sets. The 5 different IT teams would be given 2 CD sets each. They would build 1 each of the various PC classes in use, then Ghost them onto the others. So the ID and CD keys would legitimately be the same accross many PCs for any given flavor of software. Your situation may be different, but it is worth thinking about.

Gene

Edited March 18, 2004 by Gene

[bcording]

If he finds that a computer in his class is using a key readily found on the internet...it's a pretty good sign it's pirated. BTW this is pretty much the reason i posted this code. I'm using it at work as a meathod of finding out if there are any computers using products that don't conform to our volume license keys.

Edited March 18, 2004 by bcording

[insanepyrokid]

two known xp keys are the one that i use on my computer, the #1 pirated key (FCKGW-----------...)

[cherdeg]

Sorry to bump this years after...but in my case a wrong license key is returned by the function. Were there any changes since SP3 on XP?

I use the following code:

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Local $b_BinaryKey  = RegRead("HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Windows NT\CurrentVersion","DigitalProductID")
Local $s_ProductKey = _DecodeProductKey($b_BinaryKey)
$i_ButtonCliecked   = MsgBox(36, "Change Windows Product Key", "Your current" & @OSVERSION & " product key is: " & @CRLF & @CRLF & $s_ProductKey & @CRLF & @CRLF & "Do you really want to change it?")

If $i_ButtonCliecked = 6 Then

    Dim $s_VOL_PROD_KEY = InputBox("New Volume License Key", "Please enter the new key for this installation: ")
    If @error Then Exit
    $s_VOL_PROD_KEY     = StringReplace($s_VOL_PROD_KEY, "-", "")

    $o_WMIservice       = ObjGet("winmgmts:{impersonationLevel=impersonate}")
    $o_WPAinstances     = $o_WMIservice.InstancesOf("win32_WindowsProductActivation")

    for $o_Item in $o_WPAinstances
        $s_result = $o_Item.SetProductKey($s_VOL_PROD_KEY)
        If $s_result = 0 Then
            MsgBox(64, "SUCCESS", "The product key was changed.")
        Else
            MsgBox(16, "ERROR", "An error has happened, check if product key was changed.")
        EndIf
    Next

EndIf


Func _DecodeProductKey($BinaryDPID)
    Local $bKey[15]
    Local $sKey[29]
    Local $Digits[24]
    Local $Value = 0
    Local $hi = 0
    local $n = 0
    Local $i = 0
    Local $dlen = 29
    Local $slen = 15
    Local $Result

    $Digits = StringSplit("BCDFGHJKMPQRTVWXY2346789","")

    $binaryDPID = stringmid($binaryDPID,105,30)

    For $i = 1 to 29 step 2
        $bKey[int($i / 2)] = dec(stringmid($binaryDPID,$i,2))
    next

    For $i = $dlen -1 To 0 Step -1
        If Mod(($i + 1), 6) = 0 Then
            $sKey[$i] = "-"
        Else
            $hi = 0
            For $n = $slen -1 To 0 Step -1
                $Value = Bitor(bitshift($hi ,- 8) , $bKey[$n])
                $bKey[$n] = int($Value / 24)
                $hi = mod($Value , 24)
            Next
            $sKey[$i] = $Digits[$hi +1]
        EndIf

    Next
    For $i = 0 To 28
        $Result = $Result & $sKey[$i]
    Next

    Return $Result
EndFunc

I found the solution (due to tranceXXX):

If @extended = 3 Then $b_BinaryKey = Hex($b_BinaryKey)

Edited October 1, 2009 by cherdeg

[sheeva]

Work perfectly Thank's

[PeterAtkin]

Seems this does not work for Windows 7, and i seem unable to understand where the

If @extended = 3 Then $b_BinaryKey = Hex($b_BinaryKey)

should go! if that could be made transparent then is should be a doable task to make it windows 7 compliant..