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How to StringSplit only once


leuce
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G'day everyone

When I use StringSplit to create an array, the string is split at every delimiter. But is there a simple way to tell the StringSplit to split only at the first delimiter?

In other words, suppose I have this string:

$foo = 'abc#def#ghi#jkl#mno#pqr#stu#vwx#yz'

and I want this array:

$bar1 = 'abc'

$bar2 = 'def#ghi#jkl#mno#pqr#stu#vwx#yz'

...how would I do that?

I suppose I could just split by '#' and then use _ArrayToString on all array items except the first one, but is there a simpler way to do it?

Thanks

Samuel

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Use function StringInStr and search for the first occurrence of the delimiter then split manually.

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Use functions StringLeft and StringMid:

$foo = 'abc#def#ghi#jkl#mno#pqr#stu#vwx#yz'
$iPos = StringInStr($foo, "#")
$bar1 = Stringleft($foo, $iPos-1)
$bar2 = StringMid($foo, $iPos+1)
ConsoleWrite($bar1 & @LF)
ConsoleWrite($bar2 & @LF)

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Word - Wiki

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leuce,

Another way

#include <array.au3>
local $bar2 = 'def#ghi#jkl#mno#pqr#stu#vwx#yz'
$a10 = stringsplit(stringreplace($bar2,'#',0x0,1),0x0)
_arraydisplay($a10)

This assumes that you do NOT have a hex 0 in the split string.

kylomas

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Here is a third and fourth method of splitting a string on the first "#".

#include <array.au3>
Local $foo = 'abc#def#ghi#jkl#mno#pqr#stu#vwx#yz'
Local $bar1_2 = StringRegExp($foo, '(.+?)#(.+)', 3)
_ArrayDisplay($bar1_2)

;or

Local $bar1 = StringRegExpReplace($foo, '(#.+)$', "")  ; Erase from first "#", to end
Local $bar2 = StringRegExpReplace($foo, '(^.+?#)', "") ; Erase from beginning, to first "#"
MsgBox(0, "Results", "$foo = " & $foo & @LF & _
        "$bar1 = " & $bar1 & @LF & _
        "$bar2 = " & $bar2)
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  • 9 years later...

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