FileCopy Array, what am I doing wrong?

[tes5884]

I'm trying to copy the PST files to "C:\Backup". It created the backup folder. _ArrayDisplay shows that it successfully found the files. But it still doesn't copy the PST files..

Please tell me what I'm doing wrong.

Thanks!

$nMsg = GUIGetMsg()
Switch $nmsg
Case $bckuppst
$files = _RecFileListToArray("C:", "*.pst", 1, 0)
For $i = 1 To $files[0]
FileCopy($files[$i], "C:\Backup\", 8)
Next
EndSwitch

[JLogan3o13]

You would have to include the whole path in your FileCopy, since _RecFileListToArray returns just the file name. This works for me, copying from a folder with a number of .pst files in it.

#include <RecFileListToArray.au3>
#include <Array.au3>

Local $files = _RecFileListToArray(@DesktopDir & "Test", "*.pst", 1, 0)
_ArrayDisplay($files)

For $element in $files
FileCopy(@DesktopDir & "Test" & $element, "C:PSTs", 8)
Next

Edit: obviously if you're trying to scan the entire drive for the .pst files, rather than just one or two directories, this may not be the best solution.

Edited August 14, 2012 by JLogan3o13

[Mechaflash]

_RecFileListToArray allows you to specify an argument to get the entire path of the files (which is probably what you want.)

Rewrite it as:

$files = _RecFileListToArray("C:", "*.pst", 1, 0, 0, 2)

And it should work as is.

Edit:

=/

Edited August 14, 2012 by mechaflash213

[tes5884]

Or you can add the $iReturnPath value as 2 and get the full path

$files = _RecFileListToArray("C:", "*.pst", 1, 0, 0, 2)

This worked!

Thanks JLogan3o13 for pointing me in the right direction!

EDIT: Oops posted same time as mechaflash213, with the same result. Thanks for answering mechaflash213!

Edited August 14, 2012 by tes5884

[JLogan3o13]

Ah - ha, I haven't used it in so long, I forgot about that argument.