How to check if string is also number?

[E1M1]

IsNumber fails if number is formatted as string ($nr = "1234") So I need to do it other way. I cant figure out how to do it with stringregexp.

Both returns me 0.

StringRegExp("432","{0,9}")

StringRegExp("432","[:digit:]")

[bogQ]

StringIsDigit

for stringregexp i dono

Edited February 4, 2011 by bogQ

[jvanegmond]

Your regular expressions are broken because they check if the string is ONE character between 0-9. Simply repeat with * and it will work. Although I should note that the syntax is not {0,9} but [0-9]...

MsgBox(0, "", StringRegExp("432","[0-9]*"))

[E1M1]

Thanks.

[ur]

It is not accurate.

Even the below expression is giving 1.

MsgBox(0, "", StringRegExp("g432.9h","[0-9]*"))

and

MsgBox(0, "", StringRegExp("hh","[0-9]*"))

[ur]

It is not accurate.

Even the below expression is giving 1.

MsgBox(0, "", StringRegExp("g432.9h","[0-9]*"))

and

MsgBox(0, "", StringRegExp("hh","[0-9]*"))

​

[ur]

StringIsDigit is giving only for integers but not for decimal values.

MsgBox(0, "", StringIsDigit("123.89"))

Returning 0.

MsgBox(0, "", StringIsDigit("123"))

Returning 1

[jguinch]

StringIsFloat will return True, so you can use both StringIsFloat  and StringIsDigit :

$string = "1234.45"
MsgBox(0, "", StringIsDigit($string) OR StringIsFloat($string) )

For a regex :

$string = "1234.45"
MsgBox(0, "", StringRegExp($string, "^\d+(?:\.\d+)?$" ) )

 

[jchd]

Ahem, this still needs work: a number may be signed (+ or -), have no leading digit before the decimal point (e.g. .5) and then this regexp doesn't cope with reals in exp form, e.g. +123.45E-6

[jguinch]

Yes, you're right, but maybe it's enough for what the OP asks.

This one should work :

$string = "+.23E-22"

MsgBox(0, "", StringRegExp($string, "(?i)^[+-]?(?:\d+\.?(?:\d+(?:e[+-]?\d+)?)?|\.?(?:\d+(?:e[+-]?\d+)?))$" ) )

Or this way should work :

$string = "+.23E-22"
MsgBox(0, "", Execute($string) <> "" ) ; !!! returns True for an expression like "1 + 2"