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Hello again to all, I've searched many times in forum and help file to find AES-256-GCM Algorithm for Crypt\Decrypt strings and files but i did not find anything about GCM Algorithm. Do you have any idea for solving this issue?

Hi! I'm trying to script an ellipse drawing algorithm in AutoIT for learning purposes. I use an edit control to "draw" the ellipse with characters. The code i have works kinda good but i would like to see if others around here know a better algorithm to do it.. I would like to be able to give the x, y and width, height arguments to the function and not have to start at the middle point and draw the ellipse around it. side note, the ellipse glitches when it has to be 2 pixels high too.. func ellipsePlotPoints ($xc,$yc, $x,$y) pixel ($xc + $x, $yc + $y) pixel ($xc - $x, $yc + $y) pixel ($xc + $x, $yc - $y) pixel ($xc - $x, $yc - $y) endfunc func ellipse($xc,$yc, $a,$b) local $a2 = $a * $a local $b2 = $b * $b local $twoa2 = 2 * $a2 local $twob2 = 2 * $b2 local $p local $x = 0 local $y = $b local $px = 0 local $py = $twoa2 * $y ; Plot the initial point in each quadrant. ellipsePlotPoints ($xc,$yc, $x,$y) ; Region 1 $p = int($b2 - ($a2 * $b) + (0.25 * $a2)) while ($px < $py) $x+=1 $px += $twob2 if ($p < 0) then $p += $b2 + $px else $y-=1 $py -= $twoa2 $p += $b2 + $px - $py endif ellipsePlotPoints ($xc,$yc, $x,$y) wend ; Region 2 $p = int ($b2 * ($x+0.5) * ($x+0.5) + $a2 * ($y-1) * ($y-1) - $a2 * $b2) while ($y > 0) $y-=1 $py -= $twoa2 if ($p > 0) then $p += $a2 - $py else $x+=1 $px += $twob2 $p += $a2 - $py + $px endif ellipsePlotPoints ($xc,$yc, $x,$y) wend endfunc

hello guys, i have this list of youtube links: youtu.be/3bGqROF5ZWk youtu.be/mWRsgZuwf_8 youtu.be/DK_0jXPuIr0 youtu.be/NywWB67Z7zQ youtu.be/9fL5iWgWwno youtu.be/jofNR_WkoCE youtu.be/olFEpeMwgHk youtu.be/IgKWPcpwFDs and i'd like to put them between these quotes below: ElseIf $sVideoLink1 = " " then _IEAction ($oA, "click") ElseIf $sVideoLink2 = " " then _IEAction ($oA, "click") ElseIf $sVideoLink3 = " " then _IEAction ($oA, "click") ElseIf $sVideoLink4 = " " then _IEAction ($oA, "click") ElseIf $sVideoLink5 = " " then _IEAction ($oA, "click") ElseIf $sVideoLink6 = " " then _IEAction ($oA, "click") ElseIf $sVideoLink7 = " " then _IEAction ($oA, "click") but the problem is i have a lot of video links i want to put in there and everytime i put one, the VideoLinkNr. must be +1 if you know what i mean... can anyone help or give a clue

For some obvious reason, Sucessfully to translate an #computing padding algorithm, and outputting same value with example of an explanation Lets take a breath, wiki say: The following formulas provide the number of padding bytes required to align the start of a data structure (where mod is the modulo operator): # pseudo-code, see actual code below padding = (align - (offset mod align)) mod align new offset = offset + padding = offset + (align - (offset mod align)) mod align For example, the padding to add to offset 0x59d for a structure aligned to every 4 bytes is 3. The structure will then start at 0x5a0, which is a multiple of 4. Note that when offset already is a multiple of align, the second modulo in (align - (offset mod align)) mod align is required to get a padding of 0. Then I write AutoIt3 script. ConsoleWrite(@CR & '+ Computing padding' & @CR) Local $align, $offset, $padding, $new_offset $align = 4 $offset = 0x59d $padding = Mod($align - Mod($offset, $align), $align) $new_offset = $offset + $padding + Mod($offset + ($align - Mod($offset, $align)), $align) ConsoleWrite('padding: ' & $padding & ' new offset: 0x' & StringLower(Hex($new_offset, 4)) & @CR) And the output is match with example in explanation. + Computing padding padding: 3 new offset: 0x05a0 The question #01 are is that are correct translation? changing second line on second (=) (see below) with plus sign (+) in AutoIt3 (see above) ? new offset = offset + padding = offset + (align - (offset mod align)) mod align . Again lets take a breath, wiki say: If the alignment is a power of two, the modulo operation can be reduced to a bitwise boolean AND operation. The following formulas provide the new offset (where & is a bitwise AND and ~ a bitwise NOT): padding = align - (offset & (align - 1)) = (-offset) & (align - 1) new offset = (offset + align - 1) & ~(align - 1) Then I write AutoIt3 script. ConsoleWrite(@CR & '+ align 2 - Power of Two' & @CR) Local $align, $offset, $padding, $new_offset $align = 2 $offset = 0x59d $padding = $align - (BitAND($offset, ($align - 1))) + BitAND((-$offset), ($align - 1)) $new_offset = BitAND(($offset + $align - 1), BitNOT($align - 1)) ConsoleWrite('padding: ' & $padding & ' new offset: 0x' & StringLower(Hex($new_offset, 4)) & @CR) And the output is. + align 2 - Power of Two padding: 2 new offset: 0x059e The question #02. First line and second (=) I replace with plus (+) sign, again is that correct? The question #03. What is meaning from the word of 'The Power of Two'? Are 2 is The Power of Two? Are 4, 8, 16 is The Power of Two? Which are the number are is The Power of Two and which is not? Can someone give me an confirmation if translation that pseudo-code to AutoIt3 are correct.? Can someone give me an explanation what is so called 'The Power of Two'.? Please answer even if you think this are childish question, because I'm not from Brittain nor from American.