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https://msdn.microsoft.com/en-us/library/bg182625(v=vs.85).aspx Removed API feature Replacement feature document.all document.getElementById Proposal to fix: _IEQuerySelectorAll($oObject,'head',0) Currently I can not offer more help for now. I can only say that this will be fixed in future ie.au3 version (btw. status: work in progress ..... ).

Hi Argumentum! The program I'm using is specific to the company and can not even put screen print ( avoid problems with complince..rs ) . But searching here in the forum (including some answers her ) I ended up finding a solution to the problem. I used ControlCommand and ControlClick : ControlCommand("Menu Geral", "", "[CLASS:ThunderRT6ComboBox; INSTANCE:1]","SelectString","LIFE") Sleep(500) ControlClick("Menu Geral", "", "ThunderRT6CommandButton34") Thanks a lot for the help.

Use: $len = UBound($name)-1 ;Array is 0 based so 50 elements are element 0 to 49 but you try 0 to 50 $x = 0 _ArrayDisplay ($name) while $x < $len FileMove($Directory & "\" & $name[$x][0]&".svg", $Directory & "\" & $name[$x][1]&".svg" ) $x = $x+1 wend

The method is fine IMO. If there is an issue with the names as you suggest then there is no reason why you can't have both $BtnQuit = GuiCtrlCreateButton(... $Actrl[0] = $BtnQuit then when you want to refer to an individual control and make it obvious what you're doing use BtnQuit, and when you need to group them use the array. My prefered method is $grp1Start = 0 enum $Grp1 $BtnQuit=0 $ChkNever,..,$Ed1,$grp2Start enum $Grp2 $BtnSave=$grp2Start, $BtnNext,...., $grp3Start etc Global $aCtrls[20] ;create the ctrls in any order you want. ;if you need another control in an existing group just add it in the enum list somewhere. $aCtrls[$BtnNext] = GuiCtrlCreate..... ;then to deal with a group for $n = $grp2Start to $Grp3Start - 1 something($aCtrls{$n]) next which gives the understanding and flexibility, though it needs more planning. It doesn't work so well if you are using Koda though.