StringRegExp

[w0uter]

While 1
    StringRegExp('', '(a', 0)
    If @error Then ConsoleWrite('why is there only 1 error' & @LF)
WEnd

bug, or did i do something wrong.

[Valuater]

you know this one....

8)

EDIT

i tried it

the loop conntinues.... dont know

sorry

8)

EDIT 2

the @error returns "2".... so i tried these to reset the error

SetError(0)

SetExtended(0)

If @error = 2 then SetError(@error = 0)

Nopper

????

8)

Edited September 26, 2005 by Valuater

[w0uter]

ugh that means i cant finish my regexp gui.

any dev ?

[w0uter]

StringRegExp('', '(a', 0)
If @error Then ConsoleWrite('why is there only 1 error' & @LF)
    
StringRegExp('', '(b', 0)
If @error Then ConsoleWrite('why is there only 1 error' & @LF)
    
StringRegExp('', '(a', 0)
If @error Then ConsoleWrite('why is there only 1 error' & @LF)

gives 3 errors so the problem is defenetly with regexp.

but for now i have found my workaround by using a dummy regexp pattern.

still i would like to see this fixed.

Edited September 26, 2005 by w0uter

[Josbe]

Yes, maybe StringRegEx.. thing. Possibly this topic it's related.

[w0uter]

thought id bump this up so that it could be moved to Open Bugs (?)

StringRegExp('b', 'a)', 0)
If @error Then ConsoleWrite('why is there only 1 error' & @LF)
StringRegExp('b', 'a)', 0)
If @error Then ConsoleWrite('why is there only 1 error' & @LF)

Edited December 8, 2005 by w0uter